我正在尝试使用GMT值获取时区名称
我在数据库表中创建了unix时间戳.我知道用户的时区也保存在表格中,并且格式为"GMT + 04:00","GMT + 05:30"
I have unix timestamps created in a database table. I know user's timezone it is also saved in a table and int the format of "GMT+04:00" , "GMT+05:30"
我想做的是获取时间戳,并根据用户的时区向他们显示可读的时间.
What I'm trying to do is take the timestamp and show readable time to the users according to their timezone.
例如.
$startTime = '1524391500';
echo date('h:ia', $startTime) . '<br>';
date_default_timezone_set('America/Fortaleza');
echo date('h:ia', $startTime) . '<br>';
这将给我们结果
10:05am
07:05am
问题是date_default_timezone_set在此不接受时区
The problem is date_default_timezone_set doesn't accept the timezone in this
date_default_timezone_set('GMT+05:30');
所以我需要一种将"GMT + 05:30"转换为"America/Fortaleza"的方法
So I need a way to convert "GMT+05:30" to something like "America/Fortaleza"
有人可以帮我吗?
您所要求的是不可能的.时区和时区偏移是两个不同的东西.
What you ask for is not possible. A time zone and a time zone offset are two different things.
考虑一个时区,例如 America/Sao_Paulo
.在标准时间期间使用 -03:00
的偏移量,在夏时制期间使用 -02:00
的偏移量.
Consider a single time zone like America/Sao_Paulo
. It uses an offset of -03:00
during Standard Time, and an offset of -02:00
during Daylight Saving Time.
现在考虑您提到的 America/Fortaleza
在整个一年中使用 -03:00
.
Now consider that America/Fortaleza
you mentioned uses -03:00
over the entire year.
如您所见,对于给定的时区,我可能有多个偏移量,对于给定的偏移量,我可能有多个偏移量.如果您想自己寻找更多示例,可以查看时区列表及其偏移量.
As you can see, for a given time zone I may have more than one offset, and for a given offset I may have more than one time zone. You can review the lists of time zones and their offsets if you want to find more examples for yourself.
其他答案以及时区标签Wiki .