【真心求教】很短的几行ARM汇编，如何看都不懂，跪求转C的代码

【真心求教】很短的几行ARM汇编，怎么看都不懂，跪求转C的代码！

.text:0000099C                 EXPORT EncryptBound

.text:0000099C EncryptBound                            ; CODE XREF: .text:00000FEEp

.text:0000099C                                         ; Java_com_aes_touch_decryptData+34p ...

.text:0000099C                 LSLS    R3, R0, #0x1C   ; Logical Shift Left

.text:0000099E                 BEQ     locret_9AC      ; Branch

.text:000009A0                 ASRS    R3, R0, #0x1F   ; Arithmetic Shift Right

.text:000009A2                 LSRS    R3, R3, #0x1C   ; Logical Shift Right

.text:000009A4                 ADDS    R0, R3, R0      ; Rd = Op1 + Op2

.text:000009A6                 ASRS    R0, R0, #4      ; Arithmetic Shift Right

.text:000009A8                 ADDS    R0, #1          ; Rd = Op1 + Op2

.text:000009AA                 LSLS    R0, R0, #4      ; Logical Shift Left

.text:000009AC

.text:000009AC locret_9AC                              ; CODE XREF: EncryptBound+2j

.text:000009AC                 BX      LR              ; Branch to/from Thumb mode

------解决方案--------------------

typedef unsigned int uint;

int EncryptBound (int r0){

 uint r3;

 r3 = (r0 << 28);

 if(r3){

  r3 = (r0 >> 31);

  r3 >>= 28;

  r0 += r3;

  r0 >>= 4;

  r0++;

  r0 <<= 4;

 }

 return r0;

}