第12周-多继承、虚基类,继承跟组合-项目4-点、圆的关系(2)
第12周-多继承、虚基类,继承和组合-项目4-点、圆的关系(2)
/* * Copyright (c) 2014, 烟台大学计算机学院 * All rights reserved. * 文件名称:test.cpp * 作 者:刘畅 * 完成日期:2015 年 5 月 26 日 * 版 本 号:v1.0 * * 问题描述:在圆类上重载关系运算符(6种),使之能够按圆的面积比较两个圆的大小 * 输入描述:; * 程序输出:输出圆的中心、半径,圆与圆的大小关系:
代码如下:
#include <iostream> #include<Cmath> using namespace std; #define pi 3.1415926 class Point { public: Point(double a=0,double b=0):x(a),y(b) {} protected: double x,y; }; class Circle:public Point { public: Circle(double a=0,double b=0,double r=0): Point(a,b),radius(r) { } double area ( ) const; //计算圆面积 friend ostream &operator<<(ostream &,const Circle &);//重载运算符“<<” //重载关系运算符运算符,使之能够按圆的面积比较两个圆的大小; bool operator>(const Circle &); bool operator<(const Circle &); bool operator>=(const Circle &); bool operator<=(const Circle &); bool operator==(const Circle &); bool operator!=(const Circle &); protected: double radius; }; double Circle::area( ) const { return pi*radius*radius; } ostream &operator<<(ostream &output,const Circle &c) { output<<"Center=("<<c.x<<", "<<c.y<<"), r="<<c.radius; return output; } bool Circle::operator>(const Circle &c) { return (this->radius - c.radius) > 1e-7; } bool Circle::operator<(const Circle &c) { return (c.radius - this->radius) > 1e-7; } bool Circle::operator>=(const Circle &c) { return !(*this < c); } bool Circle::operator<=(const Circle &c) { return !(*this > c); } bool Circle::operator==(const Circle &c) { return abs(this->radius - c.radius) < 1e-7; } bool Circle::operator!=(const Circle &c) { return abs(this->radius - c.radius) > 1e-7; } int main( ) { Circle c1(3,2,4),c2(4,5,5); cout<<"圆c1( "<<c1<<" )的面积是 "<<c1.area()<<endl; cout<<"圆c2( "<<c2<<" )的面积是 "<<c2.area()<<endl; if(c1>c2) cout<<"圆c1大于圆c2."<<endl; if(c1<c2) cout<<"圆c1小于圆c2."<<endl; if(c1>=c2) cout<<"圆c1大于等于圆c2."<<endl; if(c1<=c2) cout<<"圆c1小于等于圆c2."<<endl; if(c1==c2) cout<<"圆c1等于圆c2."<<endl; if(c1!=c2) cout<<"圆c1不等于圆c2."<<endl; return 0; }
运行结果: