在C＃中将Hex字符串转换为普通字符串

问题描述：

我从某处将此代码转换为正常字符串。

但我无法理解这一点。有人可以解释一下吗？

在这个字符串中，第一行从字符串中取出每两个字符并将其转换为字节。

但是，我不明白为什么它们是将数组分配给字节数组的一半长度？

有时它也会出错，即如果Inputstring长度为350，字节长度为175，字符长度为87.5 ，char数组仅分配给87，这不足以容纳字节数组中的所有字符。

Hi,
I have got this code from somewhere to convert hex string to normal string.
But I cannot understand this. Can anybody explain this please ?
In this string, The first line takes each two characters from the string and convert it to byte.
But, I dont understand why they are assigning array to only half length of byte array ?

Sometimes it gets error too, i.e if Inputstring length is 350, byte length would be 175, and char length is 87.5, and char array is assigned to 87 only, thats not enough to hold all the characters in byte array.

public static string HextoString(string InputText)
{

    byte[] bb = Enumerable.Range(0, InputText.Length)
                     .Where(x => x % 2 == 0)
                     .Select(x => Convert.ToByte(InputText.Substring(x, 2), 16))
                     .ToArray();
    //return Convert.ToBase64String(bb);
    char[] chars = new char[bb.Length / sizeof(char)];
    System.Buffer.BlockCopy(bb, 0, chars, 0, bb.Length);
    return new string(chars);
}

答

解决方案4中的Rob通常是正确的...但是，如果 string是每个字符编码一个字节的十六进制编码（例如ASCII）然后它应该是正确的，具有奇数个字节。

而不是将字节转储到char数组中你应该使用正确的 System.Text.Encoding object。

Rob in Solution 4 is generally correct... However, if the string is hex encoded from a one byte per character encoding (ASCII for example) then it should be correct with an odd number of bytes.
Instead of dumping the bytes into the char array you should use the correct System.Text.Encoding object.

public static string HextoString(string InputText)
{
 
    byte[] bb = Enumerable.Range(0, InputText.Length)
                     .Where(x => x % 2 == 0)
                     .Select(x => Convert.ToByte(InputText.Substring(x, 2), 16))
                     .ToArray();
    return System.Text.Encoding.ASCII.GetString(bb);
    // or System.Text.Encoding.UTF7.GetString
    // or System.Text.Encoding.UTF8.GetString
    // or System.Text.Encoding.Unicode.GetString
    // or etc.
}

参考link [ ^ ]它正常工作。

refer answer 4 in link[^] it is working.

喜欢这样

Like so

static void Main()
{
    byte[] data = FromHex("47-61-74-65-77-61-79-53-65-72-76-65-72");
    string s = Encoding.ASCII.GetString(data); // GatewayServer
}
public static byte[] FromHex(string hex)
{
    hex = hex.Replace("-", "");
    byte[] raw = new byte[hex.Length / 2];
    for (int i = 0; i < raw.Length; i++)
    {
        raw[i] = Convert.ToByte(hex.Substring(i * 2, 2), 16);
    }
    return raw;
}

或

string hexValues = "48 65 6C 6C 6F 20 57 6F 72 6C 64 21";
string[] hexValuesSplit = hexValues.Split(' ');
foreach (String hex in hexValuesSplit)
{
    // Convert the number expressed in base-16 to an integer.
    int value = Convert.ToInt32(hex, 16);
    // Get the character corresponding to the integral value.
    string stringValue = Char.ConvertFromUtf32(value);
    char charValue = (char)value;
    Console.WriteLine("hexadecimal value = {0}, int value = {1}, char value = {2} or {3}",
                        hex, value, stringValue, charValue);
}

在C＃中将Hex字符串转换为普通字符串

相关推荐