关于排序的一段代码，求大神帮忙解决一下,该如何解决
关于排序的一段代码，求大神帮忙解决一下
- Assembly code
； 源程序是照着飒龙哥写的，问题出在输入十进制，排序后显示有错误~思考了很久，实在不会，希望大家帮忙看看。谢谢了
Student struc
number db 10 dup(' ')
student_name db 8 dup(' ')
score db 0
Student ends
stack1 segment stack
dw 100 dup(?)
stack1 ends
data segment
students Student 10 dup(<>)
real_count dw 0
flag dw 0ffffh
sort dw 10 dup(0)
buf_max db 11
count db 0
chars db 11 dup(0)
f1 db 'C:\score.txt',0
mess1 dw ?
create_error_msg db 0dh,0ah,'create file error!','$'
write_error_msg db 0dh,0ah,'write file error!','$'
enter_number db 0dh,0ah,0dh,0ah,'enter number : $'
enter_student_name db 0dh,0ah,'enter student_name : $'
enter_score db 0dh,0ah,'enter score : $'
yesorno db 0dh,0ah,'continue？ y=continue n=finish $'
mess2 db 0dh,0ah,' ',0dh,0ah
db 'number',9,9,'student_name ',9,9,'score',0dh,0ah,'$'
data ends
code segment
Assume cs:code,ds:data,es:data ,ss:stack1
start:
mov ax,data
mov ds,ax
mov es,ax
mov cx,10
mov di,offset students
mov cx,10
next:
push cx
call getnumber ;从键盘上输入number
call getstring
call getname ;从键盘上输入student_name
add di,10 ;调整变址
call getstring
call getscore
call binary
add di,8
mov [di],al
inc real_count
push dx
push ax
mov dx,offset yesorno
mov ah,9
int 21h
mov ah,1
int 21h
cmp al,'y'
jz ysno1
jmp ysno2
ysno1:
clc
jmp ysno3
ysno2:
stc
ysno3:
pop ax
pop dx
jc next1
add di,1
pop cx
loop next
next1:
call sort_score
call newline
mov dx,offset mess2
call display_string
mov cx,real_count
mov di,offset sort
loop1:
push cx
mov bx,[di]
xor si,si
mov ah,2
mov cx,10
loopnumber:
mov dl,(Student ptr [bx]).number[si]
int 21h
inc si
loop loopnumber
call table
xor si,si
mov ah,2
mov cx,8
loopname:
mov dl,(Student ptr [bx]).student_name[si]
int 21h
inc si
loop loopname
call table
call table
mov dl,(Student ptr [bx]).score
call display_number
call newline
inc di
inc di
pop cx
loop loop1
mov ah,3ch
mov cx,0
mov dx,offset f1
int 21h
jc create_error
mov mess1,ax
xor dx,dx
mov ax,19
mul real_count
mov cx,ax
mov ah,40h
mov bx,[mess1]
mov dx,offset students
int 21h
jc write_error
mov ah,3eh
mov bx,[mess1]
int 21h
exit:
mov ax,4c00h
int 21h
create_error:
mov dx,offset create_error_msg
call display_string
jmp exit
write_error:
mov dx,offset write_error_msg
call display_string
jmp exit
getnumber proc
push ax
push dx
mov ah,9
mov dx,offset enter_number
int 21h
mov [buf_max],11
mov dx,offset buf_max
mov ah,0ah
int 21h
pop dx
pop ax
ret
getnumber endp
getname proc
push ax
mov ah,9
mov dx,offset enter_student_name
int 21h
mov [buf_max],9
mov dx,offset buf_max
mov ah,0ah
int 21h
pop ax
ret
getname endp
getscore proc
push ax
mov ah,9
mov dx,offset enter_score
int 21h
mov [buf_max],4
mov dx,offset buf_max
mov ah,0ah
int 21h
pop ax
ret
getscore endp
getstring proc
push si
push di
push cx
mov si,offset chars
xor cx,cx
mov cl,count
rep movsb
pop cx
pop di
pop si
ret
getstring endp
binary proc
push bx
push cx
push dx
push si
mov si,offset chars
mov ax,0
mov dh,0
mov bx,10
loop3:
mov dl,[si]
cmp dl,0dh
jz loop4
sub dl,30h
add ax,dx
mul bx
inc si
jmp loop3
loop4:
pop si
pop dx
pop cx
pop bx
ret
binary endp
sort_score proc
push ax
push bx
push si
push di
mov bx,offset students
mov di,offset sort
mov cx,real_count
loop5:
mov al,(Student ptr [bx]).score
call insert
add bx,19
add di,2
loop loop5
pop di
pop si
pop bx
pop ax
ret
sort_score endp
insert proc
push bx
push dx
push di
mov dx,bx
loop6:
mov bx,[di-2]
cmp bx,0ffffh
jnz loop7
mov [di],dx
jmp loop9
loop7:
cmp al,(Student ptr [bx]).score
ja loop8 ;
mov [di],dx
jmp loop9
loop8:
mov [di],bx
sub di,2
jmp loop6
loop9:
pop di
pop dx
pop bx
ret
insert endp
display_number proc near
push cx
push ax
push dx
push bx
mov bx,10
xor cx,cx
loop10:
xor dx,dx
div bx
push dx
inc cx
cmp ax,0
jnz loop10
loop20:
pop dx
add dl,'0'
mov ah,2h
int 21h
loop loop20
pop bx
pop dx
pop ax
pop cx
ret
display_number endp
display_string proc
push ax
mov ah,9
int 21h
pop ax
ret
display_string endp
newline proc
push ax
push dx
mov ah,2
mov dl,0dh
int 21h
mov dl,0ah
int 21h
pop dx
pop ax
ret
newline endp
table proc
push ax
push dx
mov ah,2
mov dl,9
int 21h
pop dx
pop ax
ret
table endp
code ends
end start