为什么结果是这样的啊该如何解决

为什么结果是这样的啊
C/C++ code
#include<pthread.h>
#include<stdlib.h>
#include<stdio.h>
#include<errno.h>

pthread_cond_t taxiCond=PTHREAD_COND_INITIALIZER;

pthread_mutex_t taxiMutex=PTHREAD_MUTEX_INITIALIZER;
void * traveler_arrive(void *name)
{
    int ret;
    printf("Traveler %s needs a taxi now1\n",name);
    ret=pthread_mutex_lock(&taxiMutex);
    if (ret==0) printf("cond is locked\n");
    pthread_cond_wait(&taxiCond,&taxiMutex);
    printf("test\n");
    pthread_mutex_unlock(&taxiMutex);
    printf("%s got a taxi\n",name);
    printf("traver thread sucess and exit\n");
    pthread_exit((void *)0);
}

void * taxi_arrive(void * name)
{
    int ret;
    printf("taxi %s arrive \n",name);

    pthread_mutex_unlock(&taxiMutex);
    ret=pthread_cond_signal(&taxiCond);
    if(ret==0) printf("cond is lived\n");
    
    pthread_mutex_unlock(&taxiMutex);
    printf("taxi thread sucess and exit\n");
    pthread_exit((void *)0);
}

void main()
{
    pthread_t thread;
    pthread_attr_t threadAttr;
    pthread_attr_init(&threadAttr);

    pthread_create(&thread,&threadAttr,taxi_arrive,(void *)("Jack"));
    sleep(10);

    pthread_create(&thread,&threadAttr,traveler_arrive,(void *)("Susan"));
    sleep(10);

    pthread_create(&thread,&threadAttr,taxi_arrive,(void *)("Mike"));
    sleep(10);

    return ;

}


输出为:
taxi Jack arrive 
cond is lived
taxi thread sucess and exit
Traveler Susan needs a taxi now1
cond is locked
taxi Mike arrive 
test
Susan got a taxi
traver thread sucess and exit
cond is lived
taxi thread sucess and exit


感觉输出的结果怎么很奇怪啊:怎么 Susan got a taxi在cond is lived
那不就是信号还没出发 而那边的线程就已经得到信号了啊 这是怎么回事啊 她不是应该在等待条件为真的时候才可以将挂起的线程激活吗 怎么结果是这个样子

------解决方案--------------------
信号已经发出去了,然后你才打印的信息。
------解决方案--------------------
对,是这个意思
探讨

你的意思是 打印和发信号在操作时候并不同步 是不