功能指针作为参数
问题描述：
我尝试调用一个不带任何参数的函数指针，但是我无法使其正常工作.
I try to call a function which passed as function pointer with no argument, but I can't make it work.
void *disconnectFunc;
void D::setDisconnectFunc(void (*func)){
disconnectFunc = func;
}
void D::disconnected(){
*disconnectFunc;
connected = false;
}
答
执行此操作的正确方法是:
The correct way to do this is:
typedef void (*callback_function)(void); // type for conciseness
callback_function disconnectFunc; // variable to store function pointer type
void D::setDisconnectFunc(callback_function pFunc)
{
disconnectFunc = pFunc; // store
}
void D::disconnected()
{
disconnectFunc(); // call
connected = false;
}