Windows应用程序按钮和菜单项

问题描述：

如何创建一个在单击(普通左键)后将显示菜单项(上下文菜单)的按钮... ??

我创建了一个上下文菜单，并试图在单击按钮时显示该菜单.
它正在显示，但无法设置上下文菜单的正确位置.

这是代码:

How to create a button which will show menu items(Context Menu) after clicking(Normal Left Click) it....?

I have created a context menu and trying to show that on button click.
It is showing but can not set the proper location of context menu.

Here is Code :

private void button1_Click(object sender, EventArgs e)
{
    contextMenuStrip1.Visible = true;
    contextMenuStrip1.Left = button1.Left;
    contextMenuStrip1.Top = button1.Top - contextMenuStrip1.Height;
}

我希望右键单击按钮后，上下文菜单应该显示在按钮上方.

请帮助!!!

I want context menu should be display above the button after clicking button.

Please HELP !!!

答

我认为您正在寻找以下内容:
SplitButton:XP样式下拉拆分按钮 [

I think you are looking for this:
SplitButton: an XP style dropdown split button[^]

------

Ok so try this:

contextMenuStrip1.Show(MousePosition);

------

然后执行:

------

Then do:

Point pt = PointToScreen(button1.Location);
//or this one
//Point pt = PointToScreen(new Point(button1.Right, button1.Top));
contextMenuStrip1.Show(pt);

Windows应用程序按钮和菜单项

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