不能使用"内联"数组中的C＃？

问题描述：

想象一下，你有这样的地方

Imagine you have this somewhere

public static T AnyOne<T>(this T[] ra) where T:class
    {
    int k = ra.Length;
    int r = Random.Range(0,k);
    return ra[r];
    }

甚至只是这个

or even just this

public static string OneOf(this string[] strings)
    {
    return "a";
    }

然后，当然你也可以做到这一点...

Then, of course you can do this...

string[] st = {"a","b","c"};
string letter = st.AnyOne();

...这是伟大的。但。这样看来，你不能做到这一点：

... which is great. BUT. It would appear you can NOT do this:

string letter = {"a","b","c"}.AnyOne();

或事实上这也许

string letter = ( {"a","b","c"} ).AnyOne();

或其他任何东西我试过了。

or anything else I tried.

事实上（1）为什么人们不这样做呢？（2）我是失去了一些东西，你会怎么做，如果有一种方法？

In fact (1) why can one not do that? and (2) am I missing something, how would you do that if there is a way?

答

您必须创建数组首先，使用新[] 。

You have to create the array first, using new[].

string letter = (new[] {"a","b","c"}).AnyOne();

由于@hvd提到你可以做到这一点没有圆括号（..），我加了圆括号，因为我觉得它更具可读性。

As @hvd mentioned you can do this without parantheses (..), I added the parantheses because I think it's more readable.

string letter = new[] {"a","b","c"}.AnyOne();

和您可以指定数据类型新的String [] 作为其他的答案已经被提及。

And you can specify the data type new string[] as on other answers has been mentioned.

您不能只是做 { A，b，C} ，因为你可以把它作为一种填充数组，而不是创建它。

You can't just do {"a","b","c"}, because you can think of it as a way to populate the array, not to create it.

另一个原因将是编译器会迷茫，不知道要创造什么，例如的String [] {..} 或列表&LT;字符串方式> {...}

Another reason will be that the compiler will be confused, won't know what to create, for example, a string[]{ .. } or a List<string>{ .. }.

只需使用新[] 编译器可以通过的数据类型的（），知道 {...} ，你想要什么（字符串）。关键部分是 [] ，这意味着你需要一个数组。

Using just new[] compiler can know by data type (".."), between {..}, what you want (string). The essential part is [], that means you want an array.

您甚至无法创建一个空阵列新[] 。

You can't even create an empty array with new[].

string[] array = new []{ }; // Error: No best type found for implicity-typed array

不能使用"内联"数组中的C＃？

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