使用命令替换sed脚本里面，带参数

我试图写，我用sed来查找流的简短的脚本，然后基于一个shell功能，这需要从sed的参数结果流进行替换，例如。

I am trying to write a short script in which I use sed to search a stream, then perform a substitution on the stream based on the results of a shell function, which requires arguments from sed, e.g.

#!/bin/sh

function test {
    echo "running test"
    echo $1
    }

sed -n -e "s/.*\(00\).*/$(test)/p" < testfile.txt

在这里TESTFILE.TXT包括：

where testfile.txt contains:

1234
2345
3006
4567

（每间换行;他们越来越贵网站格式化删除）。这样就OK了剧本对我的作品（输出运行测试），但显然没有参数传递给测试。我想用sed行是这样的：

(with newlines between each; they are getting removed by your sites formatting). So ok that script works for me (output "running test"), but obviously has no arguments passed to test. I would like the sed line to be something like:

sed -n -e "s/.*\(00\).*/$(test \1)/p" < testfile.txt

和输出：

running test
00

这样sed中所匹配的模式被送入作为参数进行测试。我真的没有想到上面的工作，但我已经试过的$每个组合（）括号，反引号，和逃脱我能想到的，并且可以在任何地方找到没有提及这种情况。帮助？

So that the pattern matched by sed is fed as an argument to test. I didn't really expect the above to work, but I have tried every combination of $() brackets, backticks, and escapes I could think of, and can find no mention of this situation anywhere. Help?