在烧瓶模板中呈现html字符串

我正在建立一个网页来显示文章. 在我的数据库中，我必须具有属性，其中一个属性用于放置Markdown代码，另一个属性用于保存从Markdown代码转换而来的HTML代码.我想获取HTML并将其添加到我的基本HTML中. 我使用Flask框架和SQLAlchemy，数据保存在sqlite数据库中. 我的模特:

I'm building a web page to show articles. In my database, I have to attributes, one of which is used to put Markdown code and the other to save HTML code converted from the Markdown code. I want to get the HTML and add it to my base HTML. I use Flask framework and SQLAlchemy and the data is saved in sqlite database. My model:

class Post(db.Model):
    id = db.Column(db.Integer, primary_key=True)
    title = db.Column(db.String)
    body = db.Column(db.String)
    timestamp = db.Column(db.String)
    tag = db.Column(db.String)
    info = db.Column(db.String)
    body_markdown = db.Column(db.String)

和我的查看功能:

def post(post_id):
    post = db.session.query(Post).filter(Post.id == post_id).first()
    return render_template('post.html',
                           post = post,)

首先，我尝试过:

<div class="post-body">
    {{post.body}}
</div>

它显示带有HTML标签的整个字符串. post.body.decode("utf-8")和post.body.decode("ascii")也不起作用. 当我调试程序时，我发现数据库返回u'string'. 如何获得纯HTML代码并将其应用到基本HTML文件中?

It shows the whole string with HTML tag. post.body.decode("utf-8") and post.body.decode("ascii") didn't work, either. When I debug the program, I found that the database returns u'string'. How can I get pure HTML code and apply it in my base HTML file?