一个公式来找到素数在一个循环
问题描述:
我需要找到素数的循环或while循环
I need to find prime numbers with for loop or while loop
我写了这一点,但这样是不对的。
I wrote this but this is wrong
<?php
$i = 1;
while($i<5)
{
for($j=1; $j<=$i; $j++)
{
if ($j != 1 && $j != $i)
{
echo $i . "/" . $j . "=" . $i%$j . "<br />";
if ($i%$j != 0)
{
echo $i . "<br />";
}
}
}
echo "<br />";
$i += 1;
}
?>
有没有一种方法来划分若干使用数组找到剩下的?
Is there a way to divide a number with an array to find the remaining?
答
下面是我发现了一个小功能:(http://icdif.com/computing/2011/09/15/check-number-prime-number/)似乎为我工作!
Here's a little function that I found: (http://icdif.com/computing/2011/09/15/check-number-prime-number/) Seemed to work for me!
function isPrime($num) {
//1 is not prime. See: http://en.wikipedia.org/wiki/Prime_number#Primality_of_one
if($num == 1)
return false;
//2 is prime (the only even number that is prime)
if($num == 2)
return true;
/**
* if the number is divisible by two, then it's not prime and it's no longer
* needed to check other even numbers
*/
if($num % 2 == 0) {
return false;
}
/**
* Checks the odd numbers. If any of them is a factor, then it returns false.
* The sqrt can be an aproximation, hence just for the sake of
* security, one rounds it to the next highest integer value.
*/
for($i = 3; $i <= ceil(sqrt($num)); $i = $i + 2) {
if($num % $i == 0)
return false;
}
return true;
}