C语言编程题 输入一个百分制成绩，输出对应的五级制成绩“优秀”、“良好“、”中等“、”及格“、”不及格“，？小白求教 谢谢

#include
#include

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
int score;//定义一个成绩变量
printf("Please enter your score:");
scanf("%d",&score);//输入成绩
score=score/10;
printf("Your grade is:");
switch(score)
{
case 10:
case 9:printf("优秀\n");break;
case 8:printf("良好\n");break;
case 7:printf("中等\n");break;
case 6:printf("及格\n");break;
case 5:
case 4:
case 3:
case 2:
case 1:
case 0:printf("不及格\n");break;
}
return 0;
}

用switch或if语句都可以吧

使用（expression）？statement1：statement2语句一行搞定。

#include<iostream>
using namespace std;
int main() {
    cout << "请输入你的分数" << endl;
    int score;
    cin >> score;
    string grade;
    grade = (score >= 90) ? "优秀" : ((score >= 80) ? "良好" : ((score >= 70) ? "中等" : ((score >= 60) ? "及格" : "不及格")));
    cout << grade << endl;
    return 0;
}