在C＃中生成随机数
问题描述：
嗨。
如何在（a）和（b）之间生成n个随机数，这些数字大概是（x）？
我尝试了什么：
hi。
如何在两者之间生成n个随机数（a）和（b）围绕像（x）这样的数字？
hi.
how can i generate n random number between (a) and (b) that are around a number like (x)?
What I have tried:
hi.
how can i generate n random number between (a) and (b) that are around a number like (x)?
答
Google是你的朋友，有很多答案和细节;
随机随机=新的随机（）;
int randomvalue = random.Next（a，b + 1）;
你对像（x）这样的数字是什么意思？
Google is your friend, lots of answers and details;
Random random = new Random();
int randomvalue = random.Next(a, b + 1);
What do you mean by "on a number like (x)"?
参见这个例子： [ dotnetperls ]
See this example: [dotnetperls]
引用：
我如何在（a）和（b）之间生成n个随机数，这些数字类似于（ x）？
how can i generate n random number between (a) and (b) that are around a number like (x)?
C＃有随机函数，第一步是读取电子文档。
C# have random function, first step is to read the documentation.