解析错误：语法错误，第12行的C：\ xampp \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

问题描述：

我是新的OOP PHP学习者。我只是想创建一个表并插入我的帖子。然后我遇到了上面的Parse错误。

我尝试过：

I am new OOP PHP learner.I just wanted to create a table and insert my posts.Then I've faced Parse error above.

What I have tried:

<pre><?php
include "db.php";
include "config.php";

$db = new database();

if (isset($_POST['submit'])){
	$title = $_POST['title'];
	$content = $_POST['content'];
$query = "INSERT INTO posts(title,content) VALUES('$title',$content')"

$run=$db->insert($query);

}

?>



<!DOCTYPE html>
<html>
<head>
	<title></title>
</head>
<body>

</body>
</html>

<form action="insert_post.php" method="post" enctype="multipart/form-data">
	<div class="form-group">
	<center><table width="800" align="center" border="2">
		<tr bgcolor="orange">
		<td colspan="6"><h1 style="text-align:center">Post EDIT</h1></td>
		</tr>
		<tr>
			<td align="right" bgcolor="orange">Post title:</td>
			<td><input type="text" name="title" size="60"></td>
		</tr>
		<tr>
			<td align="right" bgcolor="orange">Post Content:</td>
			<td><textarea name="Content" rows="15" cols="40"></textarea></td>
		</tr>
     <tr>

	<td colspan="6" align="center" bgcolor="orange"><input type="Submit" name="submit" value="Publish Now"  /></td>
</tr>	






	</table>






</form>

答

db = new database（）;

if （isset（

db = new database(); if (isset(

_POST [' submit']））{

_POST['submit'])){

title =

解析错误：语法错误，第12行的C：\ xampp \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

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