小虾请教一个有关问题，关于ajax和servlet交互的有关问题~

小虾请教一个问题，关于ajax和servlet交互的问题~~~
html：

HTML code


<%@ page language="java" import="java.util.*" pageEncoding="GBK"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index_1.jsp' starting page</title>
    
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">    
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
    <link rel="stylesheet" type="text/css" href="styles.css">
    -->

  </head>
  <script type="text/javascript">
    //定义变量xmlHttp
    var xmlHttp;
    //定义函数，用来为xmlHttp赋值
    function createXMLHttpRequest(){                        
        if(window.ActiveXObject){                        
        xmlHttp= new ActiveXObject("Microsoft.XMLHTTP");                    
        }else if(window.XMLHttpRequest){                        
        xmlHttp=new XMLHttpRequest();                    
    }    
    }    
    //定义函数，向服务器发送信息                
    function sendMessage(){                        
        createXMLHttpRequest();    
        //处理缓存问题        
        
        xmlHttp.open("GET","http://localhost:80/ajax_0/servlet/Servlet_1?time="+new Date().getDay(),true);    
        xmlHttp.send(null);                    
    }                        

    
  
  </script>
  <body>
  <b>利用JavaScript的事件处理机制，通过XMLHttpRequest对象执行服务器端的程序</b><br><br><br>
  
  1、onMouseOver事件
  <a href="#" onMouseOver="sendMessage()">哈哈</a>
  <br><br><br>
  2、onClick事件
  <input type="button" value="按钮" onClick="sendMessage()" />
  <br><br><br>
  3、onBlur事件
  <input type="text" name="user" onBlur="sendMessage()"/>
  <br><br><br>
  4、onChange事件
  <input type="text" name="user" value="tianyitime" onChange="sendMessage()"/>
  <br><br><br>
  <a href="index.jsp">返回</a>
  </body>
</html>

servlet：

Java code


package com.tianyitime.ajax;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class Servlet_1 extends HttpServlet {

    /**
     * Constructor of the object.
     */
    public Servlet_1() {
        super();
    }

    /**
     * Destruction of the servlet. <br>
     */
    public void destroy() {
        super.destroy(); // Just puts "destroy" string in log
        // Put your code here
    }

    /**
     * The doGet method of the servlet. <br>
     *
     * This method is called when a form has its tag value method equals to get.
     * 
     * @param request the request send by the client to the server
     * @param response the response send by the server to the client
     * @throws ServletException if an error occurred
     * @throws IOException if an error occurred
     */
    public void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        String name = new String(request.getParameter("name").getBytes      ("ISO-8859-1"), "GBK");
System.out.println(name);

        doPost(request,response);
    }

    /**
     * The doPost method of the servlet. <br>
     *
     * This method is called when a form has its tag value method equals to post.
     * 
     * @param request the request send by the client to the server
     * @param response the response send by the server to the client
     * @throws ServletException if an error occurred
     * @throws IOException if an error occurred
     */
    public void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        String name = new String(request.getParameter("name").getBytes      ("ISO-8859-1"), "GBK");
        System.out.println(name);
        System.out.println("Servlet1执行了");
    }
    /**
     * Initialization of the servlet. <br>
     *
     * @throws ServletException if an error occure
     */
    public void init() throws ServletException {
        // Put your code here
    }

}

小虾请教一个有关问题，关于ajax和servlet交互的有关问题~

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