package LeetCode_301
import java.util.*
import kotlin.collections.ArrayList
import kotlin.collections.HashSet
/**
* 301. Remove Invalid Parentheses
* https://leetcode.com/problems/remove-invalid-parentheses/description/
*
* Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results.
Note: The input string may contain letters other than the parentheses ( and ).
Example 1:
Input: "()())()"
Output: ["()()()", "(())()"]
Example 2:
Input: "(a)())()"
Output: ["(a)()()", "(a())()"]
Example 3:
Input: ")("
Output: [""]
* */
class Solution {
/*
* solution: BFS, Time complexity:O(2^n), Space complexity:O(2^n)
* */
fun removeInvalidParentheses(s: String): List<String> {
val result = ArrayList<String>()
val visited = HashSet<String>()
val queue = LinkedList<String>()
queue.offer(s)
while (queue.isNotEmpty()) {
val cur = queue.poll()
if (visited.contains(cur)) {
continue
}
visited.add(cur)
if (isValidParenthese(cur)) {
result.add(cur)
}
//if found in this level, no need to loop again
if (result.size != 0) {
continue
}
for (i in cur.indices) {
if (cur[i] == '(' || cur[i] == ')') {
/*
check every children
* for example:()())(),
* children: remove first '('=>)())()
* remove the second:')'=>(())()
* */
val children = cur.substring(0, i) + cur.substring(i + 1, cur.length)
queue.offer(children)
}
}
}
//println(result)
return result
}
private fun isValidParenthese(s: String): Boolean {
var count = 0
for (c in s) {
if (c == '(') {
count++
} else if (c == ')') {
count--
}
if (count < 0) {
return false
}
}
return count == 0
}
}