React Native AsyncStorage getItem 返回承诺而不是价值

问题描述：

我有一个登录表单，我可以发布表单值.在成功的 POST 请求之后，我得到了从 API 返回的认证令牌.我需要将此令牌保存在本地存储中以备将来参考.为了保存这个身份验证令牌，我使用了 AsyncStorage.我使用了 AsyncStorage.setItem(STORAGE_KEY, responseData.auth_token); setItem 方法来保存数据.

I have a login form and I am able to post the form values. After the successful POST request, I get authentication token returned from the API. I need to save this token for future reference in local storage. For saving this auth token I am using AsyncStorage. I used AsyncStorage.setItem(STORAGE_KEY, responseData.auth_token); setItem method to save the data.

如果我通过以下方式控制台记录:

If I console log this by :

console.log(AsyncStorage.setItem(STORAGE_KEY));

它作为这样的承诺对象返回

it returns as promise object like this

    Promise {_45: 0, _81: 0, _65: null, _54: null}
_45
:
0
_54
:
null
_65
:
"efcc06f00eeec0b529b8"
_81
:
1
__proto__

:对象

如何从 AsyncStorage.getItem 方法中获取准确的值?

how can I get the exact value from the AsyncStorage.getItem method?

这是我的获取方法

fetch('http://54.255.201.241/drivers', {
    method: 'POST',
    headers: {
      'Accept': 'application/json',
      'Content-Type': 'application/json'
    },
    body: JSON.stringify({
      first_name: this.state.firstName,
      mobile_number: this.state.mobileNumber,
      vehicle_number: this.state.vehicleNumber,
      vehicle_type_id: 1,
    })
  }).then((response) => response.json()).then((responseData) => {
    if (JSON.stringify(responseData.mobile_number) == (this.state.mobileNumber))
    {
      AsyncStorage.setItem(STORAGE_KEY, responseData.auth_token);
      console.log(AsyncStorage.getItem(STORAGE_KEY));
      this.props.navigator.push({id: 'Otp'})
    }
    else
    {
      Alert.alert("SignUp Failed","Mobile number already taken.")  
    }
  })
  .done();

顺便说一句，他们在文档中使用了 await.我尝试使用它，但页面没有加载.这里附有截图.

BTW in documentation they have used await. I tried using that but the pages are not loading.Here with attached the screenshot.

答

使用 Async/Await :

using Async/Await :

async _getStorageValue(){
  var value = await AsyncStorage.getItem('ITEM_NAME')
  return value
}

React Native AsyncStorage getItem 返回承诺而不是价值

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