在页面中，怎么实现 右下角 自动弹出一个小窗口

在页面中，如何实现 右下角 自动弹出一个小窗口
条件是父页面也许最小化中

保证这个弹出一定是在最前面


最好是个小方框，标题栏什么的全部没有才好呢

------解决方案--------------------
<SCRIPT>
var oPopup = window.createPopup();
var popTop=50;
function popmsg(msgstr){
var winstr= " <table style=\ "border: 1 solid #6D93C8\ " width=\ "241\ " height=\ "172\ " border=\ "0\ " cellpadding=\ "0\ " cellspacing=\ "0\ " > ";
winstr+= " <tr> <td height=\ "30\ "> </td> </tr> <tr> <td align=\ "center\ "> <table width=\ "90%\ " height=\ "110\ " border=\ "0\ " cellpadding=\ "0\ " cellspacing=\ "0\ "> ";
winstr+= " <tr> <td valign=\ "top\ " style=\ "font-size:12px; color: #6D93C8; face: Tahoma\ "> "+msgstr+ " </td> </tr> </table> </td> </tr> </table> ";
oPopup.document.body.innerHTML = winstr;
popshow();
}
function popshow(){
window.status=popTop;
if(popTop> 1720){
clearTimeout(mytime);
oPopup.hide();
return;
}else if(popTop> 1520&&popTop <1720){
oPopup.show(screen.width-250,screen.height,241,1720-popTop);
}else if(popTop> 1500&&popTop <1520){
oPopup.show(screen.width-250,screen.height+(popTop-1720),241,172);
}else if(popTop <180){
oPopup.show(screen.width-250,screen.height,241,popTop);
}else if(popTop <220){
oPopup.show(screen.width-250,screen.height-popTop,241,172);
}
popTop+=10;
var mytime=setTimeout( "popshow(); ",50);
}
popmsg( "your popup window ");
</SCRIPT>
------解决方案--------------------
学习!