从bash脚本将变量传递给python函数

问题描述：

我真的很努力地试图将变量从bash脚本传递给我制作的python函数.我查看了有关同一问题的大量帖子，似乎无法理解我所缺少的内容.

I am really struggling trying to figure out to pass variables from a bash script to a python function I have made. I have looked over numberous posts about the same issue and cant seem to understand what I am missing.

我有一个名为fname_function.py的python函数脚本:

I have a python function script named fname_function.py:

from glob import glob
import os
import sys

first_arg=sys.argv[1]
second_arg=sys.argv[2]
third_arg=sys.argv[3]

def gFpath(reach,drive,date):
    list1 = glob(os.path.normpath(os.path.join(drive, reach, date,'*')))
    list2 =[]
    for afolder in list1:
      list2.append(glob(os.path.normpath(os.path.join(drive, reach, date, afolder, 'x_y_class?.asc'))))
    return list2

if __name__=='__main__':
    gFpath(first_arg,second_arg,third_arg)

我的bash脚本如下:

And my bash script looks like:

reach="R4a"
drive= "D:\\"
dte="2015_04"

fnames=$(python fname_function.py "$reach" "$drive" "$dte")

for fname in $fnames; do echo "Script returned $fname"; done

变量正在传递给python脚本，但是我似乎无法将 list2 返回到我的shell脚本.

The variables are being passed to the python script, but I cant seem to get list2 back to my shell script.

谢谢

Dubbbdan

答

您可以直接运行Python文件，例如 python fname_function.py"$ reach""$ drive""$ dte"

You can just run the Python file directly, like python fname_function.py "$reach" "$drive" "$dte"

但是，在这种情况下， sys.argv [0] 将是 fname_function.py ，因此您需要将 first_arg 设置为 sys.argv [1] 并同时增加其他数字.

However, sys.argv[0] will be fname_function.py in this case, so you'll want to set first_arg to sys.argv[1] and increment the other numbers as well.

此外，您不会在Python脚本中输出任何内容.您应该将脚本的结尾读为:

Also, you don't output anything in your Python script. You should make the end of your script read:

if __name__=='__main__':
    fnames = gFpath(first_arg,second_arg,third_arg)
    for fname in fnames:
        print(fname)

，将在每行上从 gFpath 中打印出1个结果.

which will print out 1 result from gFpath on each line.

从bash脚本将变量传递给python函数

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