从类的字符串名称中，我可以获取静态变量吗?
给出PHP中类的字符串名称，如何访问其静态变量之一?
Given the string name of a class in PHP, how can I access one of its static variables?
我想做的是这样
$className = 'SomeClass'; // assume string was actually handed in as a parameter
$foo = $className::$someStaticVar;
...但是PHP给了我一个可爱的解析错误:语法错误，意外的T_PAAMAYIM_NEKUDOTAYIM"，这显然是双冒号(::)的希伯来语名称.
...but PHP gives me a lovely "Parse error: syntax error, unexpected T_PAAMAYIM_NEKUDOTAYIM", which apparently is a Hebrew name for the double colon(::).
更新:不幸的是，我必须为此使用PHP 5.2.X.
Update: Unfortunately, I have to use PHP 5.2.X for this.
更新2:正如MrXexxed猜测的那样，静态变量是从父类继承的.
Update 2: As MrXexxed guessed, the static variable is inherited from a parent class.
反射会做到
一位同事刚刚向我展示了如何通过反射实现此功能，该功能可在PHP 5(我们在5.2上运行)中工作，所以我想我会解释一下.
Reflection will do it
A coworker just showed me how to do this with reflection, which works with PHP 5 (we're on 5.2), so I thought I'd explain.
$className = 'SomeClass';
$SomeStaticProperty = new ReflectionProperty($className, 'propertyName');
echo $SomeStaticProperty->getValue();
请参见 http://www.php.net/manual/zh/class .reflectionproperty.php
类似的技巧适用于方法.
A similar trick works for methods.
$Fetch_by_id = new ReflectionMethod($someDbmodel,'fetch_by_id');
$DBObject = $Fetch_by_id->invoke(NULL,$id);
// Now you can work with the returned object
echo $DBObject->Property1;
$DBObject->Property2 = 'foo';
$DBObject->save();
请参见 http://php.net/manual/en/class.reflectionmethod.php 和 http://www.php.net/manual/zh/Reflectionmethod.invoke.php