PHP获取包含子目录的文件列表

问题描述：

我正在尝试检索目录中的所有图像，包括所有子目录.我目前正在使用

I am trying to retrieve all images in a directory, including all subdirectories. I am currently using

$images = glob("{images/portfolio/*.jpg,images/portfolio/*/*.jpg,images/portfolio/*/*/*.jpg,images/portfolio/*/*/*/*.jpg}",GLOB_BRACE);

这可行，但是结果是:

images/portfolio/1.jpg
images/portfolio/2.jpg
images/portfolio/subdirectory1/1.jpg
images/portfolio/subdirectory1/2.jpg
images/portfolio/subdirectory2/1.jpg
images/portfolio/subdirectory2/2.jpg
images/portfolio/subdirectory1/subdirectory1/1.jpg
images/portfolio/subdirectory1/subdirectory1/2.jpg

我希望它一次执行整个目录分支，因此结果是:

I want it to do a whole directory branch at a time so the results are:

images/portfolio/1.jpg
images/portfolio/2.jpg
images/portfolio/subdirectory1/1.jpg
images/portfolio/subdirectory1/2.jpg
images/portfolio/subdirectory1/subdirectory1/1.jpg
images/portfolio/subdirectory1/subdirectory1/2.jpg
images/portfolio/subdirectory2/1.jpg
images/portfolio/subdirectory2/2.jpg

非常感谢您的帮助，欢呼！

Greatly appreciate any help, cheers!

P.S如果我只需将所有子目录放在投资组合下，而不必用通配符具体说明每个目录，那也很好.

P.S It would also be great if I could just get all subdirectories under portfolio without having to specifically state each directory with a wild card.

答

来自 glob例子

if ( ! function_exists('glob_recursive'))
{
    // Does not support flag GLOB_BRACE        
   function glob_recursive($pattern, $flags = 0)
   {
     $files = glob($pattern, $flags);
     foreach (glob(dirname($pattern).'/*', GLOB_ONLYDIR|GLOB_NOSORT) as $dir)
     {
       $files = array_merge($files, glob_recursive($dir.'/'.basename($pattern), $flags));
     }
     return $files;
   }
}

PHP获取包含子目录的文件列表

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