将多个任务的输出写入单个文件

问题描述：

在Ansible中，我编写了Yaml剧本，其中包含主机名列表和每个主机的executes命令.我已经为这些任务注册了一个变量，在执行任务结束时，我将每个命令的输出附加到单个文件中. 但是每次我尝试将其追加到输出文件时，只有最后一条记录会保留下来.

In Ansible, I have written an Yaml playbook that takes list of host name and the executes command for each host. I have registered a variable for these task and at the end of executing a task I append output of each command to a single file. But every time I try to append to my output file, only the last record is getting persisted.

---
- hosts: list_of_hosts
  become_user: some user
  vars:
    output: []
  tasks:
    - name: some name
      command: some command
      register: output
      failed_when: "'FAILED' in output"
    - debug: msg="{{output | to_nice_json}}"
    - local_action: copy content='{{output | to_nice_json}}' dest="/path/to/my/local/file"

我什至尝试使用使用insertafter参数的lineinfile追加，但未成功. 有什么我想念的吗?

I even tried to append using lineinfile using insertafter parameter yet was not successful. Anything that I am missing?

答

您可以尝试执行以下操作:

You can try something like this:

- name: dummy
  hosts: myhosts
  serial: 1
  tasks:
    - name: create file
      file:
        dest: /tmp/foo
        state: touch
      delegate_to: localhost

    - name: run cmd
      shell: echo "{{ inventory_hostname }}"
      register: op

    - name: append
      lineinfile:
        dest: /tmp/foo
        line: "{{ op }}"
        insertafter: EOF
      delegate_to: localhost

我使用了serial: 1，因为我不确定并行运行的lineinfile任务是否会使输出文件乱码.

I have used serial: 1 as I am not sure if lineinfile tasks running in parallel will garble the output file.

将多个任务的输出写入单个文件

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