如何在C#中的目录中获取文件名
问题描述：
Directory.GetFiles(targetDirectory);
使用上面的代码，我们获得目录中所有文件的名称(即完整路径).但我只需要获取文件名而不是路径.那么，如何单独获取文件名(不包括路径)呢?还是在删除不需要的部分时需要执行字符串操作?
Using the above code we get the names(i.e full path) of all the files in the directory. but i need to get only the name of the file and not the path. So how can I get the name of the files alone excluding the path? Or do I need to do the string operations in removing the unwanted part?
TreeNode mNode = new TreeNode(ofd.FileName, 2, 2);
这里 ofd 是一个 OpenFileDialog ，而 ofd.FileName 给出了文件名及其路径，但我只需要文件名.
Here ofd is a OpenFileDialog and ofd.FileName is giving the the filename along with it's Path but I need the file name alone.
答
您可以使用:
Path.GetFileName(fullPath);
或在您的示例中:
TreeNode mNode = new TreeNode(Path.GetFileName(ofd.FileName), 2, 2);