如何使用php将jpg图像转换为适当的blob数据类型
问题描述：
<?php
$file_name = $_FILES['files']['name'];
$tmp_name = $_FILES['files']['tmp_name'];
$file_size = $_FILES['files']['size'];
$file_type = $_FILES['files']['type'];
// The codes written above work fine and have proper information.
$fp = fopen($tmp_name, 'r'); // This one crashes.
$file_content = fread($fp, $file_size) or die("Error: cannot read file");
$file_content = mysql_real_escape_string($file_content) or die("Error: cannot read file");
fclose($fp);
....
我是PHP知识的新手.我正在尝试将jpg图像作为blob存储在数据库中，但是却非常挣扎:(我尝试了许多教程并阅读了文档，但仍然没有运气.任何建议或教程都可能对我有所帮助..?
I'm a newbie to PHP stuff. I'm trying to store a jpg image as blob in a database but terribly struggling with it :( I tried many tutorials and read documents but still no luck. Any suggestions or tutorials that might help me out..?
答
使用fopen()打开二进制文件时，请使用rb模式，即
When opening binary files with fopen(), use the rb mode, ie
$fp = fopen($tmp_name, 'rb');
或者，您可以简单地使用file_get_contents()，例如
Alternatively, you may simply use file_get_contents(), eg
$file_content = file_get_contents($tmp_name);
要实现更好的错误报告，请将其放在脚本顶部
To enable better error reporting, place this at the top of your script
ini_set('display_errors', 'On');
error_reporting(E_ALL);