在null上调用成员函数setCookie()
我正在尝试在幼虫中完成此中间件,以检查确保已订阅了订阅计划.如果不是该用户,它将重定向到付款页面.
I am trying to finish this middleware in larval that checks to make sure is subscribed to a subscription plan. If the user is not it redirects to the payment page.
public function handle($request, Closure $next)
{
if(Auth::check()){
if (Auth::user()->subscribed('main')) {
return true;
}else{
return view('payments.payment')->with('user',Auth::user());
}
}else{
abort(403, 'Unauthorized action.');
}
return $next($request);
}
我遇到这个错误的原因是运气不佳,无法找到解决方案.对null的成员函数setCookie()的调用.
I am getting this error with not much luck finding a solution Call to a member function setCookie() on null.
问题在于您要返回true
.中间件应返回一个响应样式的对象,而不是布尔值.
The problem is where you are returning true
. A middleware should return a response-style object, not a boolean.
由于这是您的好"路径,并且您希望继续进行应用程序逻辑,因此应将return true;
替换为return $next($request);
Since that is your "good" path and you want to proceed with your application logic, you should replace return true;
with return $next($request);
public function handle($request, Closure $next)
{
if(Auth::check()){
if (Auth::user()->subscribed('main')) {
return $next($request);
}else{
return view('payments.payment')->with('user',Auth::user());
}
}else{
abort(403, 'Unauthorized action.');
}
}
在不相关的建议下,您可以稍微整理一下条件逻辑,以使代码更易于阅读/关注:
On an unrelated recommendation, you can clean up your conditional logic a bit to make your code easier to read/follow:
public function handle($request, Closure $next)
{
// If the user is not logged in, respond with a 403 error.
if ( ! Auth::check()) {
abort(403, 'Unauthorized action.');
}
// If the user is not subscribed, show a different payments page.
if ( ! Auth::user()->subscribed('main')) {
return view('payments.payment')->with('user',Auth::user());
}
// The user is subscribed; continue with the request.
return $next($request);
}