如何使用内置函数将Inf和NaN替换为零
问题描述：
在八度音阶中，有一个内置函数可以将向量中的Inf/NaN替换为0
In octave, is there a build in function for replacing Inf/NaN to 0 in a vector
例如
a = log10([30 40 0 60]) => [1.4771 1.6021 -Inf 1.7782]
我可以使用有限或查找功能查找有效值的索引/位置 但是我不知道如何在不编写函数的情况下正确地复制值.
I can use finite or find function to find the index/position of the valid values but I don't know how to copy the values correctly without writing a function.
finite(a) => [1 1 0 1]
答
>> a = log10([30 40 0 60])
a =
1.477 1.602 -Inf 1.778
>> a(~isfinite(a))=0
a =
1.477 1.602 0 1.778
做到了，这使用了逻辑索引
~是布尔值/逻辑值的NOT运算符，并且isfinite(a)生成逻辑向量，其大小与a:
~ is the NOT operator for boolean/logical values and isfinite(a) generates a logical vector, same size as a:
>> ~isfinite(a)
ans =
0 0 1 0
如您所见，这用于逻辑索引.
As you can see, this is used for the logical indexing.