如何在PHP中解析此JSON?

问题描述：

它存储在MongoDB中，并通过json_decode.

It's stored inside MongoDB and passed to my view file with json_decode.

使用PHP，如何从内部获取值?

Using PHP, how can I grab the values from within?

"environment" : {
            "_id" : "QU",
            "name" : "QA Unstable",
            "streams" : "unstable",
            "hosts" : [
                    "deployclient1",
                    "deployclient2"
            ]
}

答

由于您已经知道json_decode，因此现在可以实际回答问题了:

Now to actually answer the question since you already know of json_decode:

使用PHP，如何从内部获取值?

Using PHP, how can I grab the values from within?

json_decode会将JSON字符串评估为PHP中的一个对象(默认情况下)，这意味着您可以使用基本的动态访问语法来获取您的值，即获取_id:

json_decode will evaluate the JSON string into a object in PHP (by default) which means you can use basic dynamic accession syntax to get to your values, i.e. to get _id:

$object->environment->_id;

或主持人:

$object->environment->hosts[0]

这将返回:deployclient1

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