如何在bash中用另一个字符替换字符串的最后一个字符?
问题描述：
我正在使用bash编写一个小代码，但是我遇到了一个小问题.我有一个字符串，我想用 s 替换该字符串的最后一个字母.
I am working on a small code in bash, but I am stuck on a small problem.
I have a string, and I want to replace the last letter of that string with s.
例如:我要提取所有以 c 结尾的文件，并用 s 替换最后一个 c .
For example: I am taking all the files that end in c and replacing the last c with s.
for file in *.c; do
# replace c with s
echo $file
有人可以帮我吗?
答
for file in *.c; do
echo "${file%?}s"
done
在参数替换中，$ {VAR％PAT}将从变量VAR中删除与PAT匹配的最后一个字符.外壳模式 * 和?可用作通配符.
In parameter substitution, ${VAR%PAT} will remove the last characters matching PAT from variable VAR.
Shell patterns * and ? can be used as wildcards.
以上内容删除了最后一个字符，并附加了"s".
The above drops the final character, and appends "s".