shell_exec()在"ls"上返回null

问题描述：

所以我有这段代码，我只想在另一个目录中创建保存列表，该目录中的php scrip位于xampp文件夹中，并且保存到此路径/root/files/saves:

So I have this code and I'm only trying to make a list of the saves in another directory where the php scrip is in xampp folder and the saves are to this path /root/files/saves:

<html>
<body>
<?php
$output = shell_exec('ls /root/files/saves');
echo "<pre>$output</pre>";
?>
</body>
</html>

我不知道为什么我不能让它在var_dump上运行，似乎输出为空，我真的感到困惑，它应该可以工作，或者我全都错了，我需要一些帮助.

I don't know why I can't get it working on a var_dump it seems output is null I'm really confuse it should work or I just it all wrong I need some help.

答

在shell命令的末尾添加2>&1以使STDERR和STDOUT都返回.

Add 2>&1 to the end of your shell command to have STDERR returned as well as STDOUT.

$output = shell_exec("ls /root/files/saves 2>&1");

此外，如果运行PHP的用户没有足够的权限来查看/root/中的输出，则以上代码将返回Permission denied错误消息.

Also, if the user running PHP don't have the sufficient permissions to view the output in /root/, then the above code will return a Permission denied error message.

来源: http://php.net/manual/en/function.shell-exec .php#28994

shell_exec()在"ls"上返回null

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