(字符串的模式匹配4.7.12)POJ 2121 Inglish-Number Translator(将英文数目字转换成阿拉伯数字)

(字符串的模式匹配4.7.12)POJ 2121 Inglish-Number Translator(将英文数字转换成阿拉伯数字)

package com.njupt.acm;

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class POJ_2121 {

	public static void main(String[] args) {
		/**
		 * negative, zero, one, two, three, four, five, six, seven, 
		 * eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen,
		 *  sixteen, seventeen, eighteen, nineteen, twenty, thirty, forty, fifty, 
		 *  sixty, seventy, eighty, ninety, hundred, thousand, million 
		 */
		Map map = new HashMap();
		map.put("negative", -1);
		map.put("zero", 0);
		map.put("one", 1);
		map.put("two", 2);
		map.put("three", 3);
		map.put("four", 4);
		map.put("five", 5);
		map.put("six", 6);
		map.put("seven", 7);
		map.put("eight", 8);
		map.put("nine", 9);
		map.put("ten", 10);
		map.put("eleven", 11);
		map.put("twelve", 12);
		map.put("thirteen", 13);
		map.put("fourteen", 14);
		map.put("fifteen", 15);
		map.put("sixteen", 16);
		map.put("seventeen", 17);
		map.put("eighteen", 18);
		map.put("nineteen", 19);
		map.put("twenty", 20);
		map.put("thirty", 30);
		map.put("forty", 40);
		map.put("fifty", 50);
		map.put("sixty", 60);
		map.put("seventy", 70);
		map.put("eighty", 80);
		map.put("ninety", 90);
		map.put("hundred", 100);
		map.put("thousand", 1000);
		map.put("million", 1000000);
		
		
		Scanner scanner = new Scanner(System.in);
		
		
		while(scanner.hasNextLine()){
			int sum = 0;//总数
			int acc = 0;//累加到某一步的数
			int flag = 1;
			String str1 = scanner.nextLine();
			
			str1 = str1.trim();
			if(str1.length()==0){
				break;
			}
			String[] strs = str1.split(" ");
			
			
			for(String str : strs){
				if(str.equals("hundred")){
					acc *= (Integer)map.get(str);
				}else if(str.equals("negative")){
					flag = -1;
				}else if(str.equals("thousand") || str.equals("million")){
					sum += acc*((Integer)map.get(str));
					acc=0;
				}else {
					acc += (Integer)map.get(str);
				}
			}
			
			System.out.println(flag*(sum+acc));
		}
		
	}
}