如何将行转置为列
问题描述:
SOHeaderId SODetailId
11004 100030
11004 100031
11004 100032
11004 100033
11004 100034
11004 100035
11004 100036
11005 100037
11005 100038
11005 100039
11005 100040
11006 100041
11006 100042
11006 100058
11006 100078
wanted it as
SOHeaderId SODetailId
11004 100030,100031,100032,100033,100034,100035,100036
11005 100037,100038,100039,100040
11006 100041,100042,100058,100078
WITH THE help of SQL Query only
我已经尝试过谷歌,但不能解决它。
I have already tried on google, but not able to solve it.
答
您不需要将行转置为列。您需要将[SODeaderId]列的不同[SODeaderId]连接到由逗号分隔的字符串中。最简单的方法之一是使用 XML PATH('')。
您的查询应该是这样的:
You don't need to transpose rows into columns. You need to concatenate [SODetailId] column values by distinct [SOHeaderId] into a string separated by commas. One of the simplest ways to do this is to use XML PATH('').
Your query should be something like this:
SELECT DISTINCT [SOHeaderId],
STUFF((SELECT ',' + CAST([SODetailId] AS VARCHAR(10))
FROM [TableName] t1
WHERE t1.[SOHeaderId] = t2.[SOHeaderId]
FOR XML PATH('')), 1, 1, '')
FROM [TableName] t2
我假设[SODetailId]的数据类型是 INT ,所以我将它转换为 VARCHAR(10)。
参考文献:
1. STUFF AND FOR XML PATH for String Concatenation [ ^ ]
2. 使用FOR XML PATH和STUFF来加强 [ ^ ]
I am assuming that the data type of [SODetailId] is INT, so I am casting it to VARCHAR(10).
References:
1. STUFF AND FOR XML PATH for String Concatenation[^]
2. Using FOR XML PATH and STUFF to CONCATENATE[^]