递归查找与特定模式匹配的所有文件

问题描述：

我需要查找(或更具体地，计数)与此模式匹配的所有文件:

I need to find (or more specifically, count) all files that match this pattern:

*/foo/*.doc

第一个通配符星号包含可变数量的子目录.

Where the first wildcard asterisk includes a variable number of subdirectories.

答

通过gnu find，您可以使用正则表达式，它(与-name不同)与整个路径匹配:

With gnu find you can use regex, which (unlike -name) match the entire path:

find . -regex '.*/foo/[^/]*.doc'

仅计算文件数:

find . -regex '.*/foo/[^/]*.doc' -printf '%i\n' | wc -l

(格式代码%i导致find打印inode号而不是文件名；与文件名不同，保证inode号不包含换行符之类的字符，因此计数更加可靠.感谢@该建议的三元组.)

(The %i format code causes find to print the inode number instead of the filename; unlike the filename, the inode number is guaranteed to not have characters like a newline, so counting is more reliable. Thanks to @tripleee for the suggestion.)

不过，我不知道这是否可以在OSX上使用.

I don't know if that will work on OSX, though.

递归查找与特定模式匹配的所有文件

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