如何从默认标量中提取字符串.
问题描述：
你好，
我在perl中有这个小代码，现在我非常确定该怎么做.我已经从csv文件int0 $ _中读取了一行，现在我需要从中提取字符串的一部分.
CSV文件中的前行将是
一；二；三；四；五；六
我需要有一个变量(标量)才能具有值
fourfive
(在四到五个之间没有分号)
我尝试了模式匹配，但没有得到正确的结果
可以提供任何帮助.
Hello,
I have this small code to do in perl and i am now very sure of how to do it. I have read a line from the csv file int0 $_and now i need to extract a part of the string from it.
Ex line in csv file would be
one;two;three;four;five;six
and i need to have a variable (a scalar) to have the value
fourfive
(without the semicolon between four and five)
i tried with pattern matching but didnt get the proper results
can any one help.
答
_，现在我需要从中提取字符串的一部分.
CSV文件中的前行将是
一；二；三；四；五；六
我需要有一个变量(标量)才能具有值
fourfive
(在四到五个之间没有分号)
我尝试了模式匹配，但没有得到正确的结果
谁能帮忙.
_and now i need to extract a part of the string from it.
Ex line in csv file would be
one;two;three;four;five;six
and i need to have a variable (a scalar) to have the value
fourfive
(without the semicolon between four and five)
i tried with pattern matching but didnt get the proper results
can any one help.
您需要的是:
What you need is this:
info =一个；两个；三个；四个；五个；六个；" @items = split(/;/，
info = "one;two;three;four;five;six;" @items = split(/;/,