使用 C# 中的 Open Xml SDK 将数据表导出到 Excel

问题描述:

我的程序能够将一些数据和数据表导出到 Excel 文件(模板)在模板中,我将数据插入到一些占位符中.它的工作非常好,但我也需要插入一个数据表......我的示例代码:

My program have ability to export some data and DataTable to Excel file (template) In the template I insert the data to some placeholders. It's works very good, but I need to insert a DataTable too... My sample code:

using (Stream OutStream = new MemoryStream())
{
    // read teamplate
    using (var fileStream = File.OpenRead(templatePath))
        fileStream.CopyTo(OutStream);

    // exporting
    Exporting(OutStream);
         
    // to start
    OutStream.Seek(0L, SeekOrigin.Begin);
            
    // out
    using (var resultFile = File.Create(resultPath))
        OutStream.CopyTo(resultFile);

下一个导出方法

private void Exporting(Stream template)
{
    using (var workbook = SpreadsheetDocument.Open(template, true, new OpenSettings                          { AutoSave = true }))
    {
        // Replace shared strings
        SharedStringTablePart sharedStringsPart = workbook.WorkbookPart.SharedStringTablePart;
        IEnumerable<Text> sharedStringTextElements = sharedStringsPart.SharedStringTable.Descendants<Text>();
           
        DoReplace(sharedStringTextElements);
        // Replace inline strings
        IEnumerable<WorksheetPart> worksheetParts = workbook.GetPartsOfType<WorksheetPart>();
          
        foreach (var worksheet in worksheetParts)
        {
            DoReplace(worksheet.Worksheet.Descendants<Text>());
        }

        int z = 40;
        foreach (System.Data.DataRow row in ExcelWorkXLSX.ToOut.Rows)
        {
            for (int i = 0; i < row.ItemArray.Count(); i++)
            { 
                ExcelWorkXLSX.InsertText(workbook, row.ItemArray.ElementAt(i).ToString(), getColumnName(i), Convert.ToUInt32(z)); }
                z++;
            }
        } 
        
    }
}

但是这个片段要输出DataTable slooooooooooooooooooooooowwwwwww...

But this fragment to output DataTable slooooooooooooooooooooooowwwwwww...

如何快速、真实地将DataTable导出到Excel?

How can I export DataTable to Excel fast and truly?

我写了这个简单的例子.这个对我有用.我只用一个里面有一张表的数据集测试了它,但我想这对你来说可能已经足够了.

I wrote this quick example. It works for me. I only tested it with one dataset with one table inside, but I guess that may be enough for you.

考虑到我将所有单元格都视为字符串(甚至不是 SharedStrings).如果您想使用 SharedStrings,您可能需要稍微调整一下我的示例.

Take into consideration that I treated all cells as String (not even SharedStrings). If you want to use SharedStrings you might need to tweak my sample a bit.

要完成这项工作,必须向项目添加 WindowsBase 和 DocumentFormat.OpenXml 引用.

享受,

private void ExportDataSet(DataSet ds, string destination)
        {
            using (var workbook = SpreadsheetDocument.Create(destination, DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook))
            {
                var workbookPart = workbook.AddWorkbookPart();

                workbook.WorkbookPart.Workbook = new DocumentFormat.OpenXml.Spreadsheet.Workbook();

                workbook.WorkbookPart.Workbook.Sheets = new DocumentFormat.OpenXml.Spreadsheet.Sheets();

                foreach (System.Data.DataTable table in ds.Tables) {

                    var sheetPart = workbook.WorkbookPart.AddNewPart<WorksheetPart>();
                    var sheetData = new DocumentFormat.OpenXml.Spreadsheet.SheetData();
                    sheetPart.Worksheet = new DocumentFormat.OpenXml.Spreadsheet.Worksheet(sheetData);

                    DocumentFormat.OpenXml.Spreadsheet.Sheets sheets = workbook.WorkbookPart.Workbook.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.Sheets>();
                    string relationshipId = workbook.WorkbookPart.GetIdOfPart(sheetPart);

                    uint sheetId = 1;
                    if (sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Count() > 0)
                    {
                        sheetId =
                            sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Select(s => s.SheetId.Value).Max() + 1;
                    }

                    DocumentFormat.OpenXml.Spreadsheet.Sheet sheet = new DocumentFormat.OpenXml.Spreadsheet.Sheet() { Id = relationshipId, SheetId = sheetId, Name = table.TableName };
                    sheets.Append(sheet);

                    DocumentFormat.OpenXml.Spreadsheet.Row headerRow = new DocumentFormat.OpenXml.Spreadsheet.Row();

                    List<String> columns = new List<string>();
                    foreach (System.Data.DataColumn column in table.Columns) {
                        columns.Add(column.ColumnName);

                        DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
                        cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
                        cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(column.ColumnName);
                        headerRow.AppendChild(cell);
                    }


                    sheetData.AppendChild(headerRow);

                    foreach (System.Data.DataRow dsrow in table.Rows)
                    {
                        DocumentFormat.OpenXml.Spreadsheet.Row newRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
                        foreach (String col in columns)
                        {
                            DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
                            cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
                            cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(dsrow[col].ToString()); //
                            newRow.AppendChild(cell);
                        }

                        sheetData.AppendChild(newRow);
                    }

                }
            }
        }