检查javascript中两个对象数组之间的区别
问题描述:
我需要一些帮助。如何在这种情况下获得差异数组:
I need some help. How can I get the array of the difference on this scenario:
var b1 = [
{ id: 0, name: 'john' },
{ id: 1, name: 'mary' },
{ id: 2, name: 'pablo' },
{ id: 3, name: 'escobar' }
];
var b2 = [
{ id: 0, name: 'john' },
{ id: 1, name: 'mary' }
];
我想要差异数组:
// [{ id: 2, name: 'pablo' }, { id: 3, name: 'escobar' }]
最优化的方法是怎样的?
How is the most optimized approach?
我试图过滤减少的数组..某事在这一行:
I´m trying to filter a reduced array.. something on this line:
var Bfiltered = b1.filter(function (x) {
return x.name !== b2.reduce(function (acc, document, index) {
return (document.name === x.name) ? document.name : false
},0)
});
console.log("Bfiltered", Bfiltered);
// returns { id: 0, name: 'john' }, { id: 2, name: 'pablo' }, { id: 3, name: 'escobar' } ]
谢谢,
机器人
答
.Filter()
和 .some()
函数将起作用
var b1 = [
{ id: 0, name: 'john' },
{ id: 1, name: 'mary' },
{ id: 2, name: 'pablo' },
{ id: 3, name: 'escobar' }
];
var b2 = [
{ id: 0, name: 'john' },
{ id: 1, name: 'mary' }
];
var res = b1.filter(item1 =>
!b2.some(item2 => (item2.id === item1.id && item2.name === item1.name)))
console.log(res);