int main(void)和int main(int argc，char * argv)

我有一个程序，其中包含一个名为main.cpp的文件.这包括int(int argc，char * argv)我也有一个带有以下代码的头文件.问题是我不能使用int main(void)，因为我已经在使用int main(int argc，char * argv)并且它们不能一起使用.我的问题是，我可以使用以下代码进行其他操作，从而不必使用int main(void).谢谢.

I have a program that has a file called main.cpp. This includes int(int argc, char *argv) I also have a header file with the code below. The problem is I can''t use int main(void) since I am already using an int main(int argc, char *argv) and they can''t be used together. My question is there something else that I can do with the code below so that I don''t have to use int main(void). Thank You.

#include <iostream>
#include <string>
#include <map>
 
using namespace std;
 
class Content {
    public:
        static Content* getContent(const string& type);
        static void printCurrentTypes();
 
    private:
        static map<string,content*> types;
        string type;
 
        Content(const string& t) : type( t ) {}
};
 
map<string,content*> Content::types;        

 
void Content::printCurrentTypes() {
    if (!types.empty()) {
        cout << "Number of instances made = " << types.size() << endl;
        for (map<string,content*>::iterator iter = types.begin(); iter != types.end(); ++iter) {
            cout << (*iter).first << endl;
        }
        cout << endl;
    }
}
 
int main(void) {
    Content::getContent("text/plain");
    Content::printCurrentTypes();
 
    Content::getContent("image/gif");
    Content::printCurrentTypes();
 
    Content::getContent("image/jpg");
    Content::printCurrentTypes();
 
    return 0;
}