使用按位运算符的条件语句

因此，我看到已经提出了这个问题，但是答案有些模糊且无济于事.好的，我只需要使用& ^〜！+ | >><<"

So I see that this question has already been asked, however the answers were a little vague and unhelpful. Okay, I need to implement a c expression using only "& ^ ~ ! + | >> <<"

表达式需要类似于:a? b:c

The expression needs to resemble: a ? b : c

因此，据我所知，表达式需要看起来像这样:

So, from what I've been able to tell, the expression needs to look something like:

return (a & b) | (~a & c)

这在a = 0时起作用，因为将其与b取和将得到零，然后or表达式将返回右侧，(~a & c)起作用，因为〜0给出全为1，而将所有c都与和c则返回c

This works when a = 0, because anding it with b will give zero, and then the or expression will return the right side, (~a & c) which works because ~0 gives all ones, and anding c with all ones returns c.

但是，当>> 0时，此功能将无效.有人可以尝试解释它的原因或解决方法吗?

However, this doesn't work when a > 0. Can someone try to explain why this is, or how to fix it?