打印十六进制值

问题描述：

我要做的就是在bootloader中打印一个数字的十六进制值。

架构：

英特尔x86

模式：真实

汇编程序：GNU AS

语法：AT& ; T

但我不知道......似乎有些不对劲。我使用一个简单的逻辑来实现同样的目标。我知道这个单词最多可以存储65535但是我无法正确打印所有数字。

Hi,
All I am trying to do is print the hexadecimal value of a number in bootloader.

Architecture:

Intel x86
Mode: real
Assembler: GNU AS
Syntax: AT&T

But I dont know...something seems to be wrong. I am using a simple logic to achieve the same. I know that word can store a maximum of 65535 but I am not able to print all numbers properly.

movw $16, %ax
call .printhexa

.printhexa:
   cmpw $16, %ax
   jl   .printhexa2
   
   movw $16, %bx
   divw %bx

   #####
   use %dx to 
   print the respective hexadecimal digit
   #####
   
   jmp .printhexa

.printhexa2:
   #####
   use %ax to
   print the respective hexadecimal digit
   #####
   
ret

你能帮忙吗？在实模式下打印十六进制是否有任何限制???

can you please help. Is there any limitation to print the hexadecimals in real mode ???

答

16，％ax
call .printhexa

.printhexa：
cmpw

16, %ax call .printhexa .printhexa: cmpw

16，％ax
jl .printhexa2

movw

16, %ax jl .printhexa2 movw

16，％bx
divw％bx

#####
使用％dx到
打印相应的十六进制数字
#####

jmp .printhexa

.printhexa2：
#####
使用％ax到
打印相应的十六进制数字
#####

ret

16, %bx divw %bx ##### use %dx to print the respective hexadecimal digit ##### jmp .printhexa .printhexa2: ##### use %ax to print the respective hexadecimal digit ##### ret

你能不能请救命。在实模式下打印十六进制是否有任何限制???

can you please help. Is there any limitation to print the hexadecimals in real mode ???

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