将列表中的元素向左旋转一个位置

我被要求编写一个函数rotate_left3(nums)，该函数采用长度3 的整数list称为nums，并返回带有元素向左旋转"的list，因此[1、2、3]产生[2、3、1].

I'm asked to write a function rotate_left3(nums) that takes a list of ints of length 3 called nums and returns a list with the elements "rotated left" so [1, 2, 3] yields [2, 3, 1].

问题要求轮换长度为3的列表，仅.我可以通过以下功能轻松地做到这一点(只要列表的长度仅为3):

The questions asks to rotate lists of length 3 only. I can easily do this by the following function (as long as the lists will only be of length 3):

def  rotate_left3(nums):
    return [nums[1]] + [nums[2]] + [nums[0]]

但是，我的问题是，如何对长度未知的列表执行相同的操作?

However, my question is, how do I do the same operation but with lists of unknown lengths?

作为初学者，我已经看到了一些复杂的解决方案.因此，如果能使解决方案尽可能简单，我将不胜感激.