计算每月的最后一个星期五在熊猫

问题描述：

我已编写此函数来获取该月的最后一个星期四

I've written this function to get the last Thursday of the month

def last_thurs_date(date):
    month=date.dt.month
    year=date.dt.year
    
    cal = calendar.monthcalendar(year, month)
    last_thurs_date = cal[4][4]
    if month < 10:
        thurday_date = str(year)+'-0'+ str(month)+'-' + str(last_thurs_date)
    else:
        thurday_date = str(year) + '-' + str(month) + '-' + str(last_thurs_date)
    return thurday_date

但它不起作用

datelist['Date'].map(lambda x: last_thurs_date(x))

日期列表在哪里

datelist = pd.DataFrame(pd.date_range(start = pd.to_datetime('01-01-2014',format='%d-%m-%Y')
                                      , end = pd.to_datetime('06-03-2019',format='%d-%m-%Y'),freq='D').tolist()).rename(columns={0:'Date'})
datelist['Date']=pd.to_datetime(datelist['Date'])

答

Jpp已添加解决方案，但只是添加了更具可读性的格式化字符串-请参见很棒的网站。

Jpp already added the solution, but just to add a slightly more readable formatted string - see this awesome website.

import calendar
def last_thurs_date(date):
    year, month = date.year, date.month
    cal = calendar.monthcalendar(year, month)
    # the last (4th week -> row) thursday (4th day -> column) of the calendar
    # except when 0, then take the 3rd week (February exception)
    last_thurs_date =  cal[4][4] if cal[4][4] > 0 else cal[3][4] 
    return f'{year}-{month:02d}-{last_thurs_date}'

还添加了一些逻辑-例如您获得了 2019-02-0 ，因为二月没有整整4周。

Also added a bit of logic - e.g. you got 2019-02-0 as February doesn't have 4 full weeks.

计算每月的最后一个星期五在熊猫

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