c + +迭代或分割UTF-8字符串为符号的阵列？

问题描述：

在搜索迭代UTF-8字符串或将其拆分成UTF-8符号的数组的一个平台和第三方-库 - 独立的方式。

Searching for a platform- and 3rd-party-library- independent way of iterating UTF-8 string or splitting it into array of UTF-8 symbols.

请张贴code片段。

解决：
http://stackoverflow.com/questions/2852895/c-iterate-or-split-utf-8-string-into-array-of-symbols#2856241

答

使用微小的独立于平台的 UTF8 CPP 库解决：

Solved using tiny platform-independent UTF8 CPP library:

    char* str = (char*)text.c_str();    // utf-8 string
    char* str_i = str;                  // string iterator
    char* end = str+strlen(str)+1;      // end iterator

    unsigned char[5] symbol = {0,0,0,0,0};

    do
    {
        uint32_t code = utf8::next(str_i, end); // get 32 bit code of a utf-8 symbol
        if (code == 0)
            continue;

        utf8::append(code, symbol); // initialize array `symbol`
    }
    while ( str_i < end );

c + +迭代或分割UTF-8字符串为符号的阵列？

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