MVC Capture网络摄像头图像,将图像文件路径保存到数据库

问题描述:

  • 从编辑"视图捕获网络摄像头图像. (工作中)
  • 为图像分配文件名和路径. (工作中)
  • 将图像保存到图像文件夹. (工作中)
  • 将图像的路径存储在数据库中. (不起作用)

这是我的Capture控制器:

Here is my Capture controller:

      public void Capture(String FileLocation)
    {
        //var FileLocation = Server.MapPath("~/Images/test.jpg");
        var stream = Request.InputStream;
        string dump;

        using (var reader = new StreamReader(stream))
            dump = reader.ReadToEnd();


        if (System.IO.File.Exists(FileLocation))
        {
            System.IO.File.Delete(FileLocation);
            System.IO.File.WriteAllBytes(FileLocation, String_To_Bytes2(dump));
        }
        else System.IO.File.WriteAllBytes(FileLocation, String_To_Bytes2(dump));


        return;

    }

这是编辑"控制器:

    [HttpPost]
    [ValidateAntiForgeryToken]
    public ActionResult Edit(TrappingEvent trappingevent)
    {

        if (ModelState.IsValid)
        {


            db.Entry(trappingevent).State = EntityState.Modified;
            db.SaveChanges();

            return RedirectToAction("Index");
        }

        ViewBag.PersonId = new SelectList(db.People, "Id", "First_Name", trappingevent.PersonId);
        return View(trappingevent);
    }

根据我的有限理解,最好将文件路径作为变量从Capture void传递到控制器以绑定到模型.

From my limited understanding it would be nice to pass the file path as a variable from the Capture void to the controller for binding to the model.

感谢您的帮助.

有效!好吧,我以回旋的方式做到了,但仍然很高兴听到建议.

Its working! Well I did it in a roundabout way and still happy to hear suggestions.

要点:

  • 当我单击捕获按钮时,我运行该功能:

  • when I click the capture button i run the function:

function CaptureAndAssignText() {
var Div = document.getElementById("ImagePath");//ImagePath is the field
// I want to bind to the model.

newText = "ID_" + @Model.Id + ".jpg";//Here I grab the Id of 
//the current model to use as the file name

Div.value = newText;//Assign the file name to the input 
//field ready for submission.

webcam.capture();//Run the capture function
}

  • 这是Capture功能(非常标准-有人可以告诉我是否需要为此准备文件吗?)

  • Here is the Capture function(fairly standard - can someone tell me if I need document ready for this?)

    $(document).ready(function () {
                            $("#Camera").webcam({
                                width: 320,
                                height: 240,
                                mode: "save",
                                swffile: "@Url.Content("~/Scripts/jscam.swf")",
                                onTick: function () { },
                                onSave: function () {
                                },
                                onCapture: function () {
                                    webcam.save("@Url.Action("Capture", "TrapActivity", new { id = @Model.Id , pid = @Model.PersonId})");
                                },
                                debug: function () { },
                                onLoad: function () { }
                            });
                       });
    

  • 这是我的控制器,经过修改后可以接受模型ID作为字符串(已包含字符串转字节"功能,以方便参考):

    Here is my controller, modified to accept the model ID as a string (have included the String to Bytes function for easy reference):

        public ActionResult Capture(string ID)
        {
            var path = Server.MapPath("~/Images/ID_" + ID + ".jpg" );
    
            //var path1 = "~/Images/test.jpg;";
    
    
    
            var stream = Request.InputStream;
            string dump;
    
            using (var reader = new StreamReader(stream))
                dump = reader.ReadToEnd();
    
    
            if (System.IO.File.Exists(path))
            {
                System.IO.File.Delete(path);
                System.IO.File.WriteAllBytes(path, String_To_Bytes2(dump));
            }
            else System.IO.File.WriteAllBytes(path, String_To_Bytes2(dump));
    
    
            return View(ID);
    
        }
    
        private byte[] String_To_Bytes2(string strInput)
        {
            int numBytes = (strInput.Length) / 2;
            byte[] bytes = new byte[numBytes];
    
            for (int x = 0; x < numBytes; ++x)
            {
                bytes[x] = Convert.ToByte(strInput.Substring(x * 2, 2), 16);
            }
    
            return bytes;
        }
    

    现在,一旦单击捕获即可.可以像提交强类型表单一样提交表单.

    Now once capture has been clicked. The form can be submitted just as if you were submitting a strongly typed form.

    此方法可能存在问题

    • 这种方式只允许存储一张图像.
    • 我以一种非常奇怪的方式存储文件路径.

    我乐于接受建议.