匹配正则表达式并反转目标字符串中的匹配项
问题描述：
基于这个问题 正则表达式 \d+(?:-\d+)+ 将匹配这个 10-3-1 和 5-0.
Based on this question Regex \d+(?:-\d+)+ will match this 10-3-1 and 5-0.
示例:
This is 10-3-1 my string
执行匹配和反转后，我希望它是这样的:
After performing the matching and reversing, I want it to be like this:
This is 1-3-10 my string
请注意，10-3-1 应该变成 1-3-10，而不是正常的字符串反转，这会导致 1-3-01.
Notice that 10-3-1 should become 1-3-10 and not normal string reverse which would result in 1-3-01.
答
一个基本的算法是:
- 从字符串中提取匹配项.
10-3-1" - 用-"字符将匹配分割成一段.
- 您现在有一个元素列表.
["10","3","1"] - 反转列表.
["1","3","10"] - 使用-"字符连接数组元素.
1-3-10" - 用新加入的字符串替换匹配项.