iPhone-Sqlite:约束失败错误
问题描述:
这是我的代码:
This is my code :
- (void) addOrder {
if(addStmt == nil) {
const char *sql = "insert into item(menuid,itemName,price,quantity,spiciness) Values( ?, ?, ?, ?,?)";
if(sqlite3_prepare_v2(database, sql, -1, &addStmt, NULL) != SQLITE_OK)
NSAssert1(0, @"Error while creating add statement. '%s'", sqlite3_errmsg(database));
}
// NSLog(@"ADDSTMT:%@",addStmt);
sqlite3_bind_int(addStmt, 1, [menuID integerValue]);
sqlite3_bind_text(addStmt, 2, [itemName UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_double(addStmt, 3, price );
sqlite3_bind_int(addStmt, 4, [quantity integerValue]);
sqlite3_bind_text(addStmt, 5, [spiciness UTF8String],-1,SQLITE_TRANSIENT);
if(SQLITE_DONE != sqlite3_step(addStmt))
NSAssert1(0, @"Error while inserting data. '%s'", sqlite3_errmsg(database));
else
menuID = [NSDecimalNumber numberWithLongLong:sqlite3_last_insert_rowid(database)];
//Reset the add statement.
sqlite3_reset(addStmt);
}
此处数据已插入数据库,但出现错误约束失败
Here data is inserted into DB but got the error "Constraint Failed"
答
此代码可能会帮助您。
hi may b this code will help you. insert data with this style.
sqlite3_stmt *stment;
stment =nil;
NSString *sql=[NSString stringWithFormat:@"insert into DateSave(Date,Name) Values('%@','%@')",Date,strTestName];
if (sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK)
{
if (sqlite3_prepare_v2(database, [sql UTF8String], -1, &stment, NULL) == SQLITE_OK)
{
sqlite3_step(stment);
testID =sqlite3_last_insert_rowid(database);
}
}
sqlite3_finalize(stment);
sqlite3_close(database);