从列表列表中获取元素
是否可以从Prolog中的列表列表中获取所有元素?
is it possible to get all elements from list of lists in Prolog?
类似的东西:我们有getElements([[[[a，b，[c]]，d，e]，f，g，[h，[i，j]]]，S)，结果是:S = [a，b，c，d，e，f，g，h，i，j] ...
Something like: We have getElements([[[a,b,[c]],d,e],f,g,[h,[i,j]]],S) and the result is: S = [a,b,c,d,e,f,g,h,i,j] ...
感谢您的帮助.
在SWI-Prolog(可能还有其他)中，您可以使用flatten/2:
In SWI-Prolog (and maybe others), you can use flatten/2:
?- flatten([[[a,b,[c]],d,e],f,g,[h,[i,j]]], S).
S = [a, b, c, d, e, f, g, h, i|...].
请注意， flatten/2的SWI-Prolog手册页包含以下语句:
Note that the SWI-Prolog manual page for flatten/2 includes the following statement:
最终需要用flatten/3表示(例如，append/3用于附加两个列表)，这是一个不好的设计.
Ending up needing flatten/3 often indicates, like append/3 for appending two lists, a bad design.
但是，该页面没有说明是否还有另一个本机谓词来代替它.
However, the page doesn't say whether there is another native predicate to replace it.
我相信将会提供更好的答案.
I'm sure a better answer will be supplied.