使用正则表达式在javascript中匹配引号引起来的字符串

问题描述：

我需要一个正则表达式来匹配

I need a regex for javascript for matching

"{any group of chars}" <-- where that last " is not preceeded by a \

示例:

... foo "bar" ...  => "bar"
... foo"bar\"" ... => "bar\""
... foo "bar" ...  goo"o"ooogle "t\"e\"st"[] => ["bar", "o", "t\"e\"st"]

实际的字符串会更长，并且可能包含多个匹配项，其中还可能包含空格或正则表达式特殊字符.

The actual strings will be longer and may contain multiple matches that could also include white space or regex special chars.

我首先尝试分解语法，但是我自己对regex不够强，我被卡住得很快，但是除了匹配包含\的情况之外，我确实做到了一切都匹配."(我认为)..

I have started by trying to break down the syntax but not being strong with regex myself I got stuck pretty fast but i did get as far as matching everything except for the case where the match contains \" (i think) ...

https://regex101.com/r/sj4HXw/1

更新:

有关我的处境的更多信息...

More about my situation ...

此正则表达式用于在我的博客文章中嵌入的代码块中语法突出显示"字符串，因此真实的示例可能看起来像这样……

This regex is to be used to "syntax highlight" strings in code blocks embedded in my blog posts so a real world example might look something like this ...

<pre id="test" class="code" data-code="csharp">
   if (ConfigurationManager.AppSettings["LogSql"] == "true")
</pre>

我正在使用以下javascript来突出显示..

And I am using the following javascript to achieve the highlight ..

var result = $("#test").text().replace(/"[^"\\]*(?:\\[\s\S][^"\\]*)*"/g, "<span class=\"string\">$1</span>");
$("#test").html(result);

由于某种原因，即使在这种情况下使用建议的答案(至少到目前为止)，我也得到了奇怪的结果.

For some reason even when the suggested answers (so far at least) are used in this context i'm getting odd results.

这可行，但是由于某些原因，将值$ 1代替了实际匹配项.

This works but puts the value $1 instead of the actual match for some reason.

答

简单方案(如OP中一样)

最有效的正则表达式(根据 unroll-the-循环原理)，您可以在此处使用

Simple scenario (as in OP)

The most efficient regex (that is written in accordance with the unroll-the-loop principle) you may use here is

"[^"\\]*(?:\\[\s\S][^"\\]*)*"

请参见 regex演示

详细信息:

" -匹配第一个"
[^" \\] * -除" 和 \
(?:\\ [\ s \ S] [^" \\] *)* -出现以下情况:
- \\ [\ s \ S] -前面带有 \ 的任何字符( [\ s \ S] )
- [^" \\] * -除" 和 \
- " - match the first "
- [^"\\]* - 0+ chars other than " and \
- (?:\\[\s\S][^"\\]*)* - zer or more occurrences of:
  - \\[\s\S] - any char ([\s\S]) with a \ in front
  - [^"\\]* - 0+ chars other than " and \
  用法:
```
// MATCHING
var rx = /"[^"\\]*(?:\\[\s\S][^"\\]*)*"/g;
var s = '    ... foo "bar" ...  goo"o"ooogle "t\\"e\\"st"[]';
var res = s.match(rx);
console.log(res);

// REPLACING
console.log(s.replace(rx, '<span>$&</span>'));
```
  如果在有效匹配之前存在转义的" ，或者在" 之前存在 \ ，则上述方法将不会工作.您将需要匹配那些 \ 并捕获所需的子字符串.
  
  If there is an escaped " before a valid match or there are \s before a ", the approach above won't work. You will need to match those \s and capture the substring you need.
```
/(?:^|[^\\])(?:\\{2})*("[^"\\]*(?:\\[\s\S][^"\\]*)*")/g
 ^^^^^^^^^^^^^^^^^^^^^^                             ^
```
  请参见另一个正则表达式演示.
  
  用法:
```
// MATCHING
var rx = /(?:^|[^\\])(?:\\{2})*("[^"\\]*(?:\\[\s\S][^"\\]*)*")/g;
var s = '    ... \\"foo "bar" ...  goo"o"ooogle "t\\"e\\"st"[]';
var m, res=[];
while (m = rx.exec(s)) {
  res.push(m[1]);
}
console.log(res);

// REPLACING
console.log(s.replace(/((?:^|[^\\])(?:\\{2})*)("[^"\\]*(?:\\[\s\S][^"\\]*)*")/g, '$1<span>$2</span>'));
```
  主模式包含捕获括号，并且将其添加在开头:
  
  The main pattern is wrapped with capturing parentheses, and this is added at the start:
  - (?:^ | [^ \\])-字符串的开头或除 \
  - (?:\\ {2})* -0次以上出现双反斜杠.
  - (?:^|[^\\]) - either start of string or any char but \
  - (?:\\{2})* - 0+ occurrences of a double backslash.

使用正则表达式在javascript中匹配引号引起来的字符串

简单方案(如OP中一样)

Simple scenario (as in OP)

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