zoj 1005 Jugs BFS

感想：这是我的第一道oj题，思路我想了很久，感觉建模能力还是不够强啊，理清楚了就好，把各个操作看成一条路，BFS就好

http://acm.zju.edu.cn/onlinejudge/showPRoblem.do?problemCode=1005

#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<string>
#include<stack>
#include<map>
#include<vector>
#include<deque>
using namespace std;
string s[7]={"fill A","fill B","empty A","empty B","pour A B","pour B A","success"}; 
vector<string> t;
struct jugs {
	int AT;
	int BT;
}; 
deque<jugs> de;
int A,B,N;
int main(){
	while(scanf("%d %d %d",&A,&B,&N)!=EOF){
		int *isread=new int[(A+2)*(B+2)];
		int *a=new int[(A+2)*(B+2)];
		int *c=new int[(A+2)*(B+2)];
		jugs em,temp1,temp2;
		em.AT=0;
		em.BT=0;
		isread[0*B+0]=1;
		de.clear();
		de.push_back(em);
		while(!de.empty()){
			temp1=de.front();
			de.pop_front();
			if(isread[A*(B+1)+temp1.BT]==0){
				temp2=temp1;
				temp2.AT=A;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=0;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
			if(isread[temp1.AT*(B+1)+B]==0){
				temp2=temp1;
				temp2.BT=B;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=1;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
			if(isread[temp1.AT+temp1.BT]==0&&temp1.AT+temp1.BT<=B){
				temp2.AT=0;
				temp2.BT=temp1.AT+temp1.BT;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=4;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
			if(temp1.AT+temp1.BT>B&&isread[(temp1.AT-B+temp1.BT)*(B+1)+B]==0){
				temp2.AT=temp1.AT-B+temp1.BT;
				temp2.BT=B;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=4;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
			if(temp1.AT+temp1.BT>A&&isread[A*(B+1)+(temp1.BT-A+temp1.AT)]==0){
				temp2.AT=A;
				temp2.BT=temp1.BT-A+temp1.AT;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=5;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
			if(isread[(temp1.AT+temp1.BT)*(B+1)]==0&&temp1.AT+temp1.BT<=A){
				temp2.BT=0;
				temp2.AT=temp1.AT+temp1.BT;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=5;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
			if(isread[temp1.BT]==0){
				temp2.AT=0;
				temp2.BT=temp1.BT;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=2;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
			if(isread[temp1.AT*(B+1)]==0){
				temp2.BT=0;
				temp2.AT=temp1.AT;
				a[temp2.AT*(B+1)+temp2.BT]=temp1.AT*(B+1)+temp1.BT;
				c[temp2.AT*(B+1)+temp2.BT]=3;
				if(temp2.BT==N)
				break;
				de.push_back(temp2);
				isread[temp2.AT*(B+1)+temp2.BT]=1;
			}
		}
		int tt=temp2.AT*(B+1)+temp2.BT;
		t.clear();
		while(tt!=0){
			t.push_back(s[c[tt]]);
			tt=a[tt];
		}
		for(int i=t.size()-1;i>=0;i--){
			cout<<t[i]<<endl;
		}
		cout<<"success"<<endl;
	}
}