PHP数组 - 同样关键的总和值时，关键是数量

问题描述：

我的情况是类似这样的主题：

My situation is similar to this thread :

Associative阵列，同样关键的和值

然而，在我的情况下，所有键数量。
我想，以减少/联合数组，其中0键是类似的，使所有其他按键的总和。

However in my case all keys are number. I would like to reduce / combine array where key 0 is similar and make a sum of all other keys.

下面是我原来的数组：

Array
(
[0] => Array
    (
        [0] => 093042
        [1] => 3
        [2] => 0
        [4] => 0
    )

[1] => Array
    (
        [0] => 222032
        [1] => 0
        [2] => 13
        [4] => 0
    )

[2] => Array
    (
        [0] => 222032
        [1] => 0
        [2] => 0
        [4] => 15
    )

[3] => Array
    (
        [0] => 152963
        [1] => 45
        [2] => 0
        [4] => 0
    )

[4] => Array
    (
        [0] => 222032
        [1] => 0
        [2] => 7
        [4] => 0
    )

)

和这里的输出我需要：

Array
(
    [0] => Array
        (
            [0] => 093042
            [1] => 3
            [2] => 0
            [4] => 0
        )
    [1] => Array
        (
            [0] => 222032
            [1] => 0
            [2] => 20
            [4] => 15
        )
    [2] => Array
        (
            [0] => 152963
            [1] => 45
            [2] => 0
            [4] => 0
        )
)

其他线程的解决办法是行不通的，因为他们使用的键名，我不知道我这怎么能适应我的情况。

The solution of other thread is not working because they use the key name and i don't know how i can adapt this to my situation.

请，如果你能给我工作液的例子。

Please if you can give me an example of working solution.

REPLY：

现在我尝试类似的东西：从其他线程以

For now i try something like that : Take from other thread

$sum = array_reduce($data, function ($a, $b) {
        if (isset($a[$b[0]])) {
             $a[$b[0]]['budget'] += $b['budget'];
        }
        else {
             $a[$b[0]] = $b;
        }
        return $a;
    });

但这个例子看起来是只为一个名为关键的预算，但在我的情况是一些和我有3个关键[1] [2] [3]怎么能不总结键1,2,4，其中0键类似于

But this example look is only for key named budget but in my case is number and i have 3 key [1] [2] [3] how can't sum key 1,2,4 where key 0 is similar

答

这应该为你工作：

基本上我只是通过您的数组循环，并检查是否已存在于 $结果元素与 $ V的第一个元素的关键。如果不是我与 array_pad初始化（）编辑阵列0 +当前foreach循环迭代数组的。

Basically I just loop through your array and check if there is already an element in $result with the key of the first element of $v. If not I initialize it with an array_pad()'ed array of 0's + the current array of the iteration of the foreach loop.

并通过 $ V 预计第一个并把它添加到结果数组中的每个元素这个我循环之后

And after this I loop through each element of $v expect the first one and add it to the result array.

最后我只是重新索引与结果数组array_values（）。

At the end I just reindex the result array with array_values().

<?php

    foreach($arr as $v){

        if(!isset($result[$v[0]]))
            $result[$v[0]] = array_pad([$v[0]], count($v), 0);

        $count = count($v);
        for($i = 1; $i < $count; $i++)
            $result[$v[0]][$i] += $v[$i];


    }

    $result = array_values($result);
    print_r($result);

?>

输出：

Array
(
    [0] => Array
        (
            [0] => 093042
            [1] => 3
            [2] => 0
            [3] => 0
        )

    [1] => Array
        (
            [0] => 222032
            [1] => 0
            [2] => 20
            [3] => 15
        )

    [2] => Array
        (
            [0] => 152963
            [1] => 45
            [2] => 0
            [3] => 0
        )

)

PHP数组 - 同样关键的总和值时，关键是数量

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