使用引号中的逗号分隔逗号分隔的字符串中的电子邮件地址

问题描述：

Say I have the following email addresses comma separated in a string:

$addrList = 'Kevin.Brine@pppg.com, Robert.Thomas@pppg.com, "Guice, Doug" <Doug.Guice@pppg.com>';

I need the following result:

[0] => Kevin.Brine@pppg.com
[1] => Robert.Thomas@pppg.com
[2] => "Guice, Doug" <Doug.Guice@pppg.com>

Seems fairly simple, but that comma in the quoted name really has thrown me in trying to find a solution using either preg_match_all or preg_split. Also we should accommodate for emails that use single quotes for names too, ie: 'smith, tom' <tom.smith@abc.com>

假设我在字符串中分隔了以下电子邮件地址： p>

   $ addrList ='Kevin.Brine @ pppg.com，Robert.Thomas @ pppg.com，“Guice，Doug”＆lt; Doug.Guice@pppg.com>'; 
  code>  pre>  
 
 我需要以下结果： p> 
 
 
  [0] =＆gt;  Kevin.Brine@pppg.com 
 [1] =＆gt;  Robert.Thomas@pppg.com 
 [2] =＆gt;  “Guice，Doug”＆lt; Doug.Guice@pppg.com> 
  code>  pre> 
 
 看起来相当简单，但引用名称中的逗号确实让我试图 使用preg_match_all或preg_split找到解决方案。 此外，我们也应该容纳使用单引号的电子邮件，即：'smith，tom'＆lt; tom.smith@abc.com>  code>  p> 
  div>

答

str_getcsv() should give you what you need, though it will strip the quotes.

EDIT

If you want to put the quotes back in:

$addrList = 'Kevin.Brine@pppg.com, Robert.Thomas@pppg.com, "Guice, Doug" <Doug.Guice@pppg.com>';


$t = str_getcsv($addrList);

foreach($t as $k => $v) {
    if (strpos($v,',') !== false) {
        $t[$k] = '"'.str_replace(' <','" <',$v);
    }
}

var_dump($t);

使用引号中的逗号分隔逗号分隔的字符串中的电子邮件地址

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